Subnetting Questions 35 | Find the number of valid subnets and hosts

Subnetting Questions 35

Enter the maximum number of valid subnets and usable hosts per subnet that you can get from the network 172.26.0.0 255.255.255.240:

Solution

255.255.255.240

(2⁷ + 2⁶ + 2⁵ + 2⁴ + 2³ + 2² + 2¹ + 2⁰) . (2⁷ + 2⁶ + 2⁵ + 2⁴ + 2³ + 2² + 2¹ + 2⁰) . (2⁷ + 2⁶ + 2⁵ + 2⁴ + 2³ + 2² + 2¹ + 2⁰) . (2⁷ + 2⁶ + 2⁵ + 2⁴)

11111111.11111111.11111111.11110000

Hence, the IP Address starts from 172 it indicates it is a Class B Address. By default in Class B Address 16 bits are reserved for the network and 16 bits reserved for the host. So we have borrowed 12 bits from the third and the fourth octet.

Find the total number of Subnets (Network)

2ⁿ (Here, n indicates the total number of network bits borrowed)

2¹² = 4096

Find the number of IP Address on each network

2ⁿ – 2 (Here, n indicates the total number of host bits. Substracted 2 because on every network the first IP is reserved for the network id and the last IP is reserved for the broadcast)

2⁴ – 2 = 14 host is available on each network